1564. Put Boxes Into the Warehouse I
Medium
You are given two arrays of positive integers, boxes
and warehouse
, representing the heights of some boxes of unit width and the heights of n
rooms in a warehouse respectively. The warehouse's rooms are labelled from 0
to n - 1
from left to right where warehouse[i]
(0-indexed) is the height of the ith
room.
Boxes are put into the warehouse by the following rules:
- Boxes cannot be stacked.
- You can rearrange the insertion order of the boxes.
- Boxes can only be pushed into the warehouse from left to right only.
- If the height of some room in the warehouse is less than the height of a box, then that box and all other boxes behind it will be stopped before that room.
Return the maximum number of boxes you can put into the warehouse.
Example 1:
Input: boxes = [4,3,4,1], warehouse = [5,3,3,4,1] Output: 3 Explanation: We can first put the box of height 1 in room 4. Then we can put the box of height 3 in either of the 3 rooms 1, 2, or 3. Lastly, we can put one box of height 4 in room 0. There is no way we can fit all 4 boxes in the warehouse.
Example 2:
Input: boxes = [1,2,2,3,4], warehouse = [3,4,1,2] Output: 3 Explanation: Notice that it's not possible to put the box of height 4 into the warehouse since it cannot pass the first room of height 3. Also, for the last two rooms, 2 and 3, only boxes of height 1 can fit. We can fit 3 boxes maximum as shown above. The yellow box can also be put in room 2 instead. Swapping the orange and green boxes is also valid, or swapping one of them with the red box.
Example 3:
Input: boxes = [1,2,3], warehouse = [1,2,3,4] Output: 1 Explanation: Since the first room in the warehouse is of height 1, we can only put boxes of height 1.
Example 4:
Input: boxes = [4,5,6], warehouse = [3,3,3,3,3] Output: 0
Constraints:
n == warehouse.length
1 <= boxes.length, warehouse.length <= 10^5
1 <= boxes[i], warehouse[i] <= 10^9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | class Solution { public int maxBoxesInWarehouse(int[] boxes, int[] warehouse) { int nb = boxes.length, nw = warehouse.length, res = 0, p = 0; Arrays.sort(boxes); for(int i=nb-1; i>=0 && p<nw; --i){ if(boxes[i]<=warehouse[p]){ p++; res++; } } return res; } } |
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