Monday, March 15, 2021

LeetCode [1302]

 1302. Deepest Leaves Sum

Medium
Given the root of a binary tree, return the sum of values of its deepest leaves.

 

Example 1:

Input: root = [1,2,3,4,5,null,6,7,null,null,null,null,8]
Output: 15

Example 2:

Input: root = [6,7,8,2,7,1,3,9,null,1,4,null,null,null,5]
Output: 19

 

Constraints:

  • The number of nodes in the tree is in the range [1, 104].
  • 1 <= Node.val <= 100

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/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    int maxSum = Integer.MIN_VALUE;
    int maxLevel = -1;
    public int deepestLeavesSum(TreeNode root) {
        if(root==null) return 0;
        helper(root, 0);
        return maxSum;
    }
    
    void helper(TreeNode node, int level){
        
        if(node==null) return;
       // System.out.println(node.val+" "+level);
        if(node.left==null && node.right==null){
            if(level==maxLevel) maxSum += node.val;
            else if(level>maxLevel){
                maxSum = node.val;
                maxLevel = level;
            } 
        }else{
            helper(node.left, level+1);
            helper(node.right, level+1);
        }
    }
}

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