LeetCode [1462] Course Schedule IV

 1462. Course Schedule IV

Medium

There are a total of n courses you have to take, labeled from 0 to n-1.

Some courses may have direct prerequisites, for example, to take course 0 you have first to take course 1, which is expressed as a pair: [1,0]

Given the total number of courses n, a list of direct prerequisite pairs and a list of queries pairs.

You should answer for each queries[i] whether the course queries[i][0] is a prerequisite of the course queries[i][1] or not.

Return a list of boolean, the answers to the given queries.

Please note that if course a is a prerequisite of course b and course b is a prerequisite of course c, then, course a is a prerequisite of course c.

 

Example 1:

Input: n = 2, prerequisites = [[1,0]], queries = [[0,1],[1,0]]
Output: [false,true]
Explanation: course 0 is not a prerequisite of course 1 but the opposite is true.

Example 2:

Input: n = 2, prerequisites = [], queries = [[1,0],[0,1]]
Output: [false,false]
Explanation: There are no prerequisites and each course is independent.

Example 3:

Input: n = 3, prerequisites = [[1,2],[1,0],[2,0]], queries = [[1,0],[1,2]]
Output: [true,true]

Example 4:

Input: n = 3, prerequisites = [[1,0],[2,0]], queries = [[0,1],[2,0]]
Output: [false,true]

Example 5:

Input: n = 5, prerequisites = [[0,1],[1,2],[2,3],[3,4]], queries = [[0,4],[4,0],[1,3],[3,0]]
Output: [true,false,true,false]

 

Constraints:

• 2 <= n <= 100
• 0 <= prerequisite.length <= (n * (n - 1) / 2)
• 0 <= prerequisite[i][0], prerequisite[i][1] < n
• prerequisite[i][0] != prerequisite[i][1]
• The prerequisites graph has no cycles.
• The prerequisites graph has no repeated edges.
• 1 <= queries.length <= 10^4
• queries[i][0] != queries[i][1]

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class Solution { public List<Boolean> checkIfPrerequisite(int n, int[][] prerequisites, int[][] queries) { int[][] path = new int[n][n]; for(int[] p : prerequisites){ path[p[0]][p[1]] = 1; } for(int k=0; k<n; ++k){ for(int i=0; i<n; ++i){ for(int j=0; j<n; ++j){ // System.out.println(i+" " + k+ " "+j); path[i][j] |= path[i][k]&path[k][j]; } } } List<Boolean> ret = new ArrayList<>(); for(int[] q : queries){ ret.add(path[q[0]][q[1]] == 1); } return ret; } }