1038. Binary Search Tree to Greater Sum Tree
Medium
Given the root of a binary search tree with distinct values, modify it so that every node
has a new value equal to the sum of the values of the original tree that are greater than or equal to node.val
.
As a reminder, a binary search tree is a tree that satisfies these constraints:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
Example 1:
Input: [4,1,6,0,2,5,7,null,null,null,3,null,null,null,8] Output: [30,36,21,36,35,26,15,null,null,null,33,null,null,null,8]
Constraints:
- The number of nodes in the tree is between
1
and100
. - Each node will have value between
0
and100
. - The given tree is a binary search tree.
Note: This question is the same as 538: https://leetcode.com/problems/convert-bst-to-greater-tree/
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode() {} * TreeNode(int val) { this.val = val; } * TreeNode(int val, TreeNode left, TreeNode right) { * this.val = val; * this.left = left; * this.right = right; * } * } */ class Solution { int tmp = 0; public TreeNode bstToGst(TreeNode root) { if(root == null) return null; root.right = bstToGst(root.right); root.val += tmp; tmp = root.val; root.left = bstToGst(root.left); return root; } }
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