Given an array
A
of integers, return the length of the longest arithmetic subsequence in A
.
Recall that a subsequence of
A
is a list A[i_1], A[i_2], ..., A[i_k]
with 0 <= i_1 < i_2 < ... < i_k <= A.length - 1
, and that a sequence B
is arithmetic if B[i+1] - B[i]
are all the same value (for 0 <= i < B.length - 1
).
Example 1:
Input: [3,6,9,12] Output: 4 Explanation: The whole array is an arithmetic sequence with steps of length = 3.
Example 2:
Input: [9,4,7,2,10] Output: 3 Explanation: The longest arithmetic subsequence is [4,7,10].
Example 3:
Input: [20,1,15,3,10,5,8] Output: 4 Explanation: The longest arithmetic subsequence is [20,15,10,5].
Note:
2 <= A.length <= 2000
0 <= A[i] <= 10000
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 | class Solution { public: int longestArithSeqLength(vector<int>& A) { unordered_map<int, unordered_map<int, int>> dp;//dp[diff][index] is the subsequence lenght with "diff" at "index" int n = A.size(), ret = 0; for(int i=0; i<n; ++i) { for(int j=i+1; j<n; ++j) { int diff = A[j]-A[i]; dp[diff][j] = dp[diff].count(i) ? dp[diff][i]+1 : 2; ret = max(ret, dp[diff][j]); } } return ret; } }; |
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