740. Delete and Earn
Medium
Given an array nums
of integers, you can perform operations on the array.
In each operation, you pick any nums[i]
and delete it to earn nums[i]
points. After, you must delete every element equal to nums[i] - 1
or nums[i] + 1
.
You start with 0 points. Return the maximum number of points you can earn by applying such operations.
Example 1:
Input: nums = [3, 4, 2] Output: 6 Explanation: Delete 4 to earn 4 points, consequently 3 is also deleted. Then, delete 2 to earn 2 points. 6 total points are earned.
Example 2:
Input: nums = [2, 2, 3, 3, 3, 4] Output: 9 Explanation: Delete 3 to earn 3 points, deleting both 2's and the 4. Then, delete 3 again to earn 3 points, and 3 again to earn 3 points. 9 total points are earned.
Note:
- The length of
nums
is at most20000
. - Each element
nums[i]
is an integer in the range[1, 10000]
.
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 | class Solution { /* p2 p1 p0 p2 p1 */ public int deleteAndEarn(int[] nums) { int n = 10001; int[] sum = new int[n]; int max = 0; for(int i : nums) sum[i] += i; int p1 = 0, p2 = 0; for(int i=0; i<n; ++i){ //max earned point until current position int p0 = Math.max(sum[i]+p2, p1); p2 = Math.max(p1, p2); p1 = p0; max = Math.max(max, p0); } return max; } } |
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