Monday, July 25, 2016

LeetCode [350] Intersection of Two Arrays II

350. Intersection of Two Arrays II
Easy

Given two arrays, write a function to compute their intersection.

Example 1:

Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2,2]

Example 2:

Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [4,9]

Note:

  • Each element in the result should appear as many times as it shows in both arrays.
  • The result can be in any order.

Follow up:

  • What if the given array is already sorted? How would you optimize your algorithm?
  • What if nums1's size is small compared to nums2's size? Which algorithm is better?
  • What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
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class Solution {
public:
    vector<int> intersect(vector<int>& nums1, vector<int>& nums2) {
        unordered_map<int, int> mp;//number, count
        for(auto n:nums1) mp[n]++;
        vector<int> ret;
        for(auto n:nums2){
            if(mp.count(n) && mp[n]>0){
                mp[n]--;
                ret.push_back(n);
            }
        }
        return ret;
    }
};

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